2y^2+10y-325=0

Solution for 2y^2+10y-325=0 equation:

2y^2+10y-325=0

a = 2; b = 10; c = -325;
Δ = b2-4ac
Δ = 102-4·2·(-325)
Δ = 2700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2700}=\sqrt{900*3}=\sqrt{900}*\sqrt{3}=30\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-30\sqrt{3}}{2*2}=\frac{-10-30\sqrt{3}}{4}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+30\sqrt{3}}{2*2}=\frac{-10+30\sqrt{3}}{4}
$